jquery - Error in update and insert query in php mysql -


i trying update seen(a bool in database) if seen button clicked , delete row if delete button clicked. doesn't seem work nor data(mysql_error) back. last else part works , data.

this php code :

if(isset($_post["seen"])){     $fid=$_post["id"];     $sql="update feedback set seen=1 id=$fid";     mysql_query($sql,$con);     echo mysql_error($con); } else if(isset($_post["delete"])){     $fid=$_post["id"];     $sql="delete feedback id=$fid";     mysql_query($sql,$con);     echo mysql_error($con); } else{     $sql="select * feedback";     $result=mysql_query($sql,$con);     while($row=mysql_fetch_array($result)){         $jsondata[]=$row;     }     echo json_encode($jsondata); } 

and js code:

$("#seen").click(function(){     $.post("main_php.php",{},function(data){         alert(data);     });  });  $("#delete").click(function(){     var fid = $('#id').val();     $.post("main_php.php",{id:fid},function(data){         console.log(data);     })  }); 

please tell me may wrong it!!!!

seen , delete names of buttons btw

your jquery post not setting "seen" or "delete". when php executes, falling through last else.

in jquery, set "seen" or "delete" true (or else, need set) , should good.


Comments

Popular posts from this blog

c - How to retrieve a variable from the Apache configuration inside the module? -

c# - Constructor arguments cannot be passed for interface mocks -

python - malformed header from script index.py Bad header -